x^2+44x+120=0

Solution for x^2+44x+120=0 equation:

x^2+44x+120=0

a = 1; b = 44; c = +120;
Δ = b2-4ac
Δ = 442-4·1·120
Δ = 1456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1456}=\sqrt{16*91}=\sqrt{16}*\sqrt{91}=4\sqrt{91}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-4\sqrt{91}}{2*1}=\frac{-44-4\sqrt{91}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+4\sqrt{91}}{2*1}=\frac{-44+4\sqrt{91}}{2}
$